Optimal. Leaf size=316 \[ \frac{\left (x^2+1\right ) \sqrt{\frac{x^2+2}{2 x^2+2}} (2 d-e) \text{EllipticF}\left (\tan ^{-1}(x),\frac{1}{2}\right )}{2 d \sqrt{x^4+3 x^2+2} (d-e)^2}+\frac{e^2 x \sqrt{x^4+3 x^2+2}}{2 d \left (d^2-3 d e+2 e^2\right ) \left (d+e x^2\right )}-\frac{e x \left (x^2+2\right )}{2 d \sqrt{x^4+3 x^2+2} \left (d^2-3 d e+2 e^2\right )}-\frac{e \left (x^2+2\right ) \left (3 d^2-6 d e+2 e^2\right ) \Pi \left (1-\frac{e}{d};\tan ^{-1}(x)|\frac{1}{2}\right )}{2 \sqrt{2} d^2 \sqrt{\frac{x^2+2}{x^2+1}} \sqrt{x^4+3 x^2+2} (d-2 e) (d-e)^2}+\frac{e \left (x^2+1\right ) \sqrt{\frac{x^2+2}{x^2+1}} E\left (\tan ^{-1}(x)|\frac{1}{2}\right )}{\sqrt{2} d \sqrt{x^4+3 x^2+2} (d-2 e) (d-e)} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.326668, antiderivative size = 399, normalized size of antiderivative = 1.26, number of steps used = 9, number of rules used = 8, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {1223, 1716, 1189, 1099, 1135, 1214, 1456, 539} \[ \frac{e^2 x \sqrt{x^4+3 x^2+2}}{2 d \left (d^2-3 d e+2 e^2\right ) \left (d+e x^2\right )}-\frac{e x \left (x^2+2\right )}{2 d \sqrt{x^4+3 x^2+2} \left (d^2-3 d e+2 e^2\right )}+\frac{\left (x^2+1\right ) \sqrt{\frac{x^2+2}{x^2+1}} \left (3 d^2-6 d e+2 e^2\right ) F\left (\tan ^{-1}(x)|\frac{1}{2}\right )}{2 \sqrt{2} d \sqrt{x^4+3 x^2+2} (d-2 e) (d-e)^2}-\frac{e \left (x^2+2\right ) \left (3 d^2-6 d e+2 e^2\right ) \Pi \left (1-\frac{e}{d};\tan ^{-1}(x)|\frac{1}{2}\right )}{2 \sqrt{2} d^2 \sqrt{\frac{x^2+2}{x^2+1}} \sqrt{x^4+3 x^2+2} (d-2 e) (d-e)^2}-\frac{\left (x^2+1\right ) \sqrt{\frac{x^2+2}{x^2+1}} F\left (\tan ^{-1}(x)|\frac{1}{2}\right )}{2 \sqrt{2} \sqrt{x^4+3 x^2+2} (d-2 e) (d-e)}+\frac{e \left (x^2+1\right ) \sqrt{\frac{x^2+2}{x^2+1}} E\left (\tan ^{-1}(x)|\frac{1}{2}\right )}{\sqrt{2} d \sqrt{x^4+3 x^2+2} (d-2 e) (d-e)} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 1223
Rule 1716
Rule 1189
Rule 1099
Rule 1135
Rule 1214
Rule 1456
Rule 539
Rubi steps
\begin{align*} \int \frac{1}{\left (d+e x^2\right )^2 \sqrt{2+3 x^2+x^4}} \, dx &=\frac{e^2 x \sqrt{2+3 x^2+x^4}}{2 d \left (d^2-3 d e+2 e^2\right ) \left (d+e x^2\right )}-\frac{\int \frac{-2 \left (d^2-3 d e+e^2\right )+2 d e x^2+e^2 x^4}{\left (d+e x^2\right ) \sqrt{2+3 x^2+x^4}} \, dx}{2 d (d-2 e) (d-e)}\\ &=\frac{e^2 x \sqrt{2+3 x^2+x^4}}{2 d \left (d^2-3 d e+2 e^2\right ) \left (d+e x^2\right )}+\frac{\int \frac{-d e^2-e^3 x^2}{\sqrt{2+3 x^2+x^4}} \, dx}{2 d (d-2 e) (d-e) e^2}+\frac{\left (3 d^2-6 d e+2 e^2\right ) \int \frac{1}{\left (d+e x^2\right ) \sqrt{2+3 x^2+x^4}} \, dx}{2 d (d-2 e) (d-e)}\\ &=\frac{e^2 x \sqrt{2+3 x^2+x^4}}{2 d \left (d^2-3 d e+2 e^2\right ) \left (d+e x^2\right )}-\frac{\int \frac{1}{\sqrt{2+3 x^2+x^4}} \, dx}{2 (d-2 e) (d-e)}+\frac{\left (3 d^2-6 d e+2 e^2\right ) \int \frac{1}{\sqrt{2+3 x^2+x^4}} \, dx}{2 d (d-2 e) (d-e)^2}-\frac{\left (e \left (3 d^2-6 d e+2 e^2\right )\right ) \int \frac{2+2 x^2}{\left (d+e x^2\right ) \sqrt{2+3 x^2+x^4}} \, dx}{4 d (d-2 e) (d-e)^2}-\frac{e \int \frac{x^2}{\sqrt{2+3 x^2+x^4}} \, dx}{2 d \left (d^2-3 d e+2 e^2\right )}\\ &=-\frac{e x \left (2+x^2\right )}{2 d \left (d^2-3 d e+2 e^2\right ) \sqrt{2+3 x^2+x^4}}+\frac{e^2 x \sqrt{2+3 x^2+x^4}}{2 d \left (d^2-3 d e+2 e^2\right ) \left (d+e x^2\right )}+\frac{e \left (1+x^2\right ) \sqrt{\frac{2+x^2}{1+x^2}} E\left (\tan ^{-1}(x)|\frac{1}{2}\right )}{\sqrt{2} d (d-2 e) (d-e) \sqrt{2+3 x^2+x^4}}-\frac{\left (1+x^2\right ) \sqrt{\frac{2+x^2}{1+x^2}} F\left (\tan ^{-1}(x)|\frac{1}{2}\right )}{2 \sqrt{2} (d-2 e) (d-e) \sqrt{2+3 x^2+x^4}}+\frac{\left (3 d^2-6 d e+2 e^2\right ) \left (1+x^2\right ) \sqrt{\frac{2+x^2}{1+x^2}} F\left (\tan ^{-1}(x)|\frac{1}{2}\right )}{2 \sqrt{2} d (d-2 e) (d-e)^2 \sqrt{2+3 x^2+x^4}}-\frac{\left (e \left (3 d^2-6 d e+2 e^2\right ) \sqrt{1+\frac{x^2}{2}} \sqrt{2+2 x^2}\right ) \int \frac{\sqrt{2+2 x^2}}{\sqrt{1+\frac{x^2}{2}} \left (d+e x^2\right )} \, dx}{4 d (d-2 e) (d-e)^2 \sqrt{2+3 x^2+x^4}}\\ &=-\frac{e x \left (2+x^2\right )}{2 d \left (d^2-3 d e+2 e^2\right ) \sqrt{2+3 x^2+x^4}}+\frac{e^2 x \sqrt{2+3 x^2+x^4}}{2 d \left (d^2-3 d e+2 e^2\right ) \left (d+e x^2\right )}+\frac{e \left (1+x^2\right ) \sqrt{\frac{2+x^2}{1+x^2}} E\left (\tan ^{-1}(x)|\frac{1}{2}\right )}{\sqrt{2} d (d-2 e) (d-e) \sqrt{2+3 x^2+x^4}}-\frac{\left (1+x^2\right ) \sqrt{\frac{2+x^2}{1+x^2}} F\left (\tan ^{-1}(x)|\frac{1}{2}\right )}{2 \sqrt{2} (d-2 e) (d-e) \sqrt{2+3 x^2+x^4}}+\frac{\left (3 d^2-6 d e+2 e^2\right ) \left (1+x^2\right ) \sqrt{\frac{2+x^2}{1+x^2}} F\left (\tan ^{-1}(x)|\frac{1}{2}\right )}{2 \sqrt{2} d (d-2 e) (d-e)^2 \sqrt{2+3 x^2+x^4}}-\frac{e \left (3 d^2-6 d e+2 e^2\right ) \left (2+x^2\right ) \Pi \left (1-\frac{e}{d};\tan ^{-1}(x)|\frac{1}{2}\right )}{2 \sqrt{2} d^2 (d-2 e) (d-e)^2 \sqrt{\frac{2+x^2}{1+x^2}} \sqrt{2+3 x^2+x^4}}\\ \end{align*}
Mathematica [C] time = 0.583131, size = 175, normalized size = 0.55 \[ \frac{\frac{e^2 x \left (x^4+3 x^2+2\right )}{\left (d^2-3 d e+2 e^2\right ) \left (d+e x^2\right )}+\frac{i \sqrt{x^2+1} \sqrt{x^2+2} \left (d (d-e) \text{EllipticF}\left (i \sinh ^{-1}\left (\frac{x}{\sqrt{2}}\right ),2\right )+\left (-3 d^2+6 d e-2 e^2\right ) \Pi \left (\frac{2 e}{d};\left .i \sinh ^{-1}\left (\frac{x}{\sqrt{2}}\right )\right |2\right )+d e E\left (\left .i \sinh ^{-1}\left (\frac{x}{\sqrt{2}}\right )\right |2\right )\right )}{d (d-2 e) (d-e)}}{2 d \sqrt{x^4+3 x^2+2}} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [C] time = 0.026, size = 443, normalized size = 1.4 \begin{align*}{\frac{{e}^{2}x}{2\, \left ({d}^{2}-3\,de+2\,{e}^{2} \right ) d \left ( e{x}^{2}+d \right ) }\sqrt{{x}^{4}+3\,{x}^{2}+2}}+{\frac{{\frac{i}{4}}\sqrt{2}{\it EllipticF} \left ({\frac{i}{2}}x\sqrt{2},\sqrt{2} \right ) }{{d}^{2}-3\,de+2\,{e}^{2}}\sqrt{2\,{x}^{2}+4}\sqrt{{x}^{2}+1}{\frac{1}{\sqrt{{x}^{4}+3\,{x}^{2}+2}}}}-{\frac{{\frac{i}{4}}e\sqrt{2}{\it EllipticF} \left ({\frac{i}{2}}x\sqrt{2},\sqrt{2} \right ) }{ \left ({d}^{2}-3\,de+2\,{e}^{2} \right ) d}\sqrt{2\,{x}^{2}+4}\sqrt{{x}^{2}+1}{\frac{1}{\sqrt{{x}^{4}+3\,{x}^{2}+2}}}}+{\frac{{\frac{i}{4}}e\sqrt{2}{\it EllipticE} \left ({\frac{i}{2}}x\sqrt{2},\sqrt{2} \right ) }{ \left ({d}^{2}-3\,de+2\,{e}^{2} \right ) d}\sqrt{2\,{x}^{2}+4}\sqrt{{x}^{2}+1}{\frac{1}{\sqrt{{x}^{4}+3\,{x}^{2}+2}}}}-{\frac{{\frac{3\,i}{2}}\sqrt{2}}{{d}^{2}-3\,de+2\,{e}^{2}}\sqrt{1+{\frac{{x}^{2}}{2}}}\sqrt{{x}^{2}+1}{\it EllipticPi} \left ({\frac{i}{2}}x\sqrt{2},2\,{\frac{e}{d}},\sqrt{2} \right ){\frac{1}{\sqrt{{x}^{4}+3\,{x}^{2}+2}}}}+{\frac{3\,ie\sqrt{2}}{ \left ({d}^{2}-3\,de+2\,{e}^{2} \right ) d}\sqrt{1+{\frac{{x}^{2}}{2}}}\sqrt{{x}^{2}+1}{\it EllipticPi} \left ({\frac{i}{2}}x\sqrt{2},2\,{\frac{e}{d}},\sqrt{2} \right ){\frac{1}{\sqrt{{x}^{4}+3\,{x}^{2}+2}}}}-{\frac{i{e}^{2}\sqrt{2}}{ \left ({d}^{2}-3\,de+2\,{e}^{2} \right ){d}^{2}}\sqrt{1+{\frac{{x}^{2}}{2}}}\sqrt{{x}^{2}+1}{\it EllipticPi} \left ({\frac{i}{2}}x\sqrt{2},2\,{\frac{e}{d}},\sqrt{2} \right ){\frac{1}{\sqrt{{x}^{4}+3\,{x}^{2}+2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{x^{4} + 3 \, x^{2} + 2}{\left (e x^{2} + d\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{x^{4} + 3 \, x^{2} + 2}}{e^{2} x^{8} +{\left (2 \, d e + 3 \, e^{2}\right )} x^{6} +{\left (d^{2} + 6 \, d e + 2 \, e^{2}\right )} x^{4} +{\left (3 \, d^{2} + 4 \, d e\right )} x^{2} + 2 \, d^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{\left (x^{2} + 1\right ) \left (x^{2} + 2\right )} \left (d + e x^{2}\right )^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{x^{4} + 3 \, x^{2} + 2}{\left (e x^{2} + d\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]